43. Stirling Numbers Stirling numbers of the first kind and of the second kind can be computed as follows: s1←{0=⍵:,1 ⋄ (0,t)+(t,0)× ⍵-1⊣t←∇ ⍵-1} s2←{0=⍵:,1 ⋄ (0,t)+(t,0)×⍳⍵+1⊣t←∇ ⍵-1} s1⍤0 ⍳7 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 1 0 0 0 0 0 2 3 1 0 0 0 0 6 11 6 1 0 0 0 24 50 35 10 1 0 0 120 274 225 85 15 1 s2⍤0 ⍳7 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 1 0 0 0 0 0 1 3 1 0 0 0 0 1 7 6 1 0 0 0 1 15 25 10 1 0 0 1 31 90 65 15 1 The two kinds are related in a simple way: (s1⍤0 ⍳7) ≡ | ⌹ s2⍤0 ⍳7 1 (s2⍤0 ⍳7) ≡ | ⌹ s1⍤0 ⍳7 1 That is, the matrix of Stirling numbers of one kind are the absolute values of the matrix inverse of the matrix of Stirling numbers of the other kind. pascal← {0=⍵:,1 ⋄ (0,t)+(t,0)⊣t←∇ ⍵-1} pascal⍤0 ⍳7 1 0 0 0 0 0 0 1 1 0 0 0 0 0 1 2 1 0 0 0 0 1 3 3 1 0 0 0 1 4 6 4 1 0 0 1 5 10 10 5 1 0 1 6 15 20 15 6 1
Appeared in J in
[119,
120].
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